SOLUTION: Solve the equation. http://www.ccaurora.edu/mat090/Tests/test_chapter_8_files/image050.gif ...._____ 8)/ 3x + 1 -1=x (that is the sqrt symbol to start the problem)

Algebra ->  Equations -> SOLUTION: Solve the equation. http://www.ccaurora.edu/mat090/Tests/test_chapter_8_files/image050.gif ...._____ 8)/ 3x + 1 -1=x (that is the sqrt symbol to start the problem)       Log On


   

Question 33197: Solve the equation.
http://www.ccaurora.edu/mat090/Tests/test_chapter_8_files/image050.gif
...._____
8)/ 3x + 1 -1=x (that is the sqrt symbol to start the problem)

A) 0, 2

B) 0

C) 2

D) 0, 1
How do I enter this problem to solve it myself?
Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
Sqrt(3x+1) - 1 = x
=> Sqrt(3x+1) = (x+1)
=> [Sqrt(3x+1)]^2 = (x+1)^2
=> 3x+1 = x^2+2x+1
=> x^2-x=0
=> x(x-) = 0
=> x= 0 or x=1
Answer: Correct Option is D