SOLUTION: If 3x^2 – 2x + 7 = 0, then (x – 13)^2= I DON'T GET IT ALL CAN YOU HELP ME?

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Question 329788: If 3x^2 – 2x + 7 = 0, then (x – 13)^2=
I DON'T GET IT ALL CAN YOU HELP ME?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2 – 2x + 7 = 0, then (x – 13)^2
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x=1/3 + 2sqrt(5)/3 * i, x= 1/3 - 2sqrt(5)/3 * i [quadratic formula below]
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((1/3 + 2sqrt(5)/3 * i)-13)^2= 1424/9 - 152sqrt(5)/9 * i ANSWER
((1/3 - 2sqrt(5)/3 * i)-13)^2= 1424/9 + 152sqrt(5)/9 * i ANSWER
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Ed
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 3x%5E2%2B-2x%2B7+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-2%29%5E2-4%2A3%2A7=-80.

The discriminant -80 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -80 is + or - sqrt%28+80%29+=+8.94427190999916.

The solution is

Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B-2%2Ax%2B7+%29