SOLUTION: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft. I know that A = W(L) so I think it should look lik

Algebra ->  Equations -> SOLUTION: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft. I know that A = W(L) so I think it should look lik      Log On


   

Question 326290: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft.
I know that A = W(L)
so I think it should look like 84=x(x+8).
I also know the dimensions are 6ft by 14ft. I just can't figure out how to solve the equation once it moves to 84= x^2(8x)
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


So far, so good. . Looks like it has the makings of a quadratic equation.



Let's see, -6 times 14 is -84 and -6 plus 14 is 8, so:



So:


or



Discard the negative root because you are looking for a positive measure of length.

The width is 6, hence the length is 6 plus 8 = 14.


John