You can put this solution on YOUR website! x^2=12 + 5x
=> x^2-5x-12 = 0
Per quadratic formula, roots of ax^2+bx+c are
x=[-b+sqrt(b^2-4ac)]/2a and x=[-b-sqrt(b^2-4ac)]/2a
In this example, a=1, b=-5, and c=-12
So, x= [5+sqrt(25+48)]/2 and x= [5-sqrt(25+48)]/2
=> x = [5+sqrt(73)]/2 and x = [5-sqrt(73)]/2
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