Question 324823: Can someone please help me with this equation?
log(x) + log(x - 99,990) = 6
x = ______
Jerry
jerry@san.rr.com
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Can someone please help me with this equation?
log(x) + log(x - 99,990) = 6
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log[x(x-99,990)] = 6
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x^2-99,900x = 10*6
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x^2 -99,900x - 1,000,000 = 0
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Quadratic Formula:
x = [99900 +- sqrt(99900^2 - 4000000)]/2
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x = [99900 +- 99880]/2
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x = 10 or x =99890
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Cheers,
Stan H.
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