SOLUTION: Please help me solve this word problem equation, A store mixes Kenyan coffee worth $10 per kilogram and Turkish coffee worth $12 per kilogram.The mixture is to sell for $11 per

Algebra ->  Equations -> SOLUTION: Please help me solve this word problem equation, A store mixes Kenyan coffee worth $10 per kilogram and Turkish coffee worth $12 per kilogram.The mixture is to sell for $11 per       Log On


   

Question 313942: Please help me solve this word problem equation,
A store mixes Kenyan coffee worth $10 per kilogram and Turkish coffee worth $12 per kilogram.The mixture is to sell for $11 per kilogram.Find how much of each should be used to make a 588-kilogram mixture.
How many kilograms of the Kenyan coffee should be in the mixture?
How many kilograms of the Turkish coffee should be in the mixture?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
12X+10(588-X)=588*11
12X+5,880-10X=6,468
2X=6,468-5,880
2X=588
X=588/2
X=294 POUNDS OF $12 COFFEE IS USED.
588-294=294 LOUNDS OF $10 COFFEE IS USED.
PROOF:
12*294+10*294=588*11
3,528+2,940=6,468
6,468=6,468