SOLUTION: if k=(u-a)/s
and k(s) = u-a
then what do I do to the formula above to get a alone?
a = u - k(s) this is the answer but I don't know what to do to "u" to get it on the other s
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-> SOLUTION: if k=(u-a)/s
and k(s) = u-a
then what do I do to the formula above to get a alone?
a = u - k(s) this is the answer but I don't know what to do to "u" to get it on the other s
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Question 302470: if k=(u-a)/s
and k(s) = u-a
then what do I do to the formula above to get a alone?
a = u - k(s) this is the answer but I don't know what to do to "u" to get it on the other side of the equation. Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! if k=(u-a)/s
and k(s) = u-a (I don't see the relevance of this)
then what do I do to the formula above to get a alone?
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k=(u-a)/s
ks = u-a
-a = ks-u
a = u - ks
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You can put this solution on YOUR website! if k=(u-a)/s
and k(s) = u-a
Solve for "a".
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Solve each equation for "u":
u-a = ks
u-a = k(s)
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u = a+ks
u = a+k(s)
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It appears the following is true:
a = u-ks
a = u-k(s)
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ks must equal k(s)
Cheers,
Stan H.
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