SOLUTION: an airplace travels 1800 miles against the wind for 6 hours. The return trip takes 5 hours. Find the speed of the airplane in still air and the speed of the wind. I know the an

Algebra ->  Equations -> SOLUTION: an airplace travels 1800 miles against the wind for 6 hours. The return trip takes 5 hours. Find the speed of the airplane in still air and the speed of the wind. I know the an      Log On


   



Question 300378: an airplace travels 1800 miles against the wind for 6 hours. The return trip takes 5 hours. Find the speed of the airplane in still air and the speed of the wind.
I know the answer is 30 mph wind speed, and 330 cruising speed. I can figure it out in my head, I just do not know the proper equation to plug the numbers into.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not sure how you figure it out in your head without an equation???
.
.
.
Let the plane speed be S and the wind speed be W.
Remember rate multipled by time equals distance.
Against the wind,
1.%28S-W%296=1800
2.%28S%2BW%295=1800
You can simplify each equation.
1.S-W=300
2.S%2BW=360
Add the two equations together to get rid of W.
2S=660
highlight_green%28+S=330%29
Then from eq. 2,
330%2BW=360
highlight_green%28+W=30%29