SOLUTION: (T+3/2)^2=7/2

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Question 299446: (T+3/2)^2=7/2
Answer by checkley77(12844) About Me  (Show Source):
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(T+3/2)^2=7/2
T^2+3T+9/4=7/2
T^2+3T+9/4-7/2=0
T^2+3T+(9-7*2)/4=0
T^2+3T(9-14)/4=0
T^2+3T-5/4
T^2+3T+1.25=0
T+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
T=(-3+-SQRT[3^2-4*1*-1.25])/2
T=(-3+-SQRT[9+5)/2
T=(-3+-SQRT14)/2
T=(-3+-3.742)/2
T=(-3+3.742)/2
T=.742/2
T=.371 ANS.
T=(-3-3.742)/2
T=(-6.742)/2
T=-3.371 ANS.