Question 27811: 1.2x-10+13+1=5x+11
2.8x/3-3=2x/3+15
3.12x/5+5=29-3x/5
4.2x/5-2=12x/5+11
5.3x/7-4=24x/7+8 Found 2 solutions by sdmmadam@yahoo.com, ali.m:Answer by sdmmadam@yahoo.com(530) (Show Source):
You can put this solution on YOUR website! 1.2x-10+13+1=5x+11
-10+13+1-11= 5x - 2x (taking 2x to the right and bringing 11 to the left)
(change side then change sign)
(-10-11)+(13+1) = 3x (by additive commutativity and associativity)
-21+14 =3x
-7 = 3x
(-7)/3 = x (dividing both the sides by 3)
Therefor x = -7/3
Verification: Put x=-7/3 on the LHS. You get (-14/3) +4 = (-14+12)/3 = -2/3
RHS = 5x+11 = 5X(-7/3) + 11 = (33-35)/3 = -2/3 LHS
Therefore x = -7/3 is right
Note: The advantage of commutativity is you can pluck a term from some position on a side and place it in some other position on the same side along with the sign of course.(transplantation!)
2.8x/3-3=2x/3+15
(8x/3- 2x/3) = 15+3 (transposing, that is changing side)
(8x-2x)/3 = 18
6x/3 = 18
2x =18
x=9
Answer: x = 9
Verification: for x=9 LHS = 21 =RHS
3.12x/5+5=29-3x/5
12x/5+3x/5 = 29 - 5
(12x+3x)/5 = 24
15x/5 = 24
3x=24
x = 24/3 = 8
x=8
Verification: LHS = (96/5+5) = 121/5
RHS = (29-24/5) = (145-24)/5 = 121/5 = LHS
Therefore x = 8 is correct