SOLUTION: solve for x. {{{3(10^2^x+1)=5(10^2^x-1)}}}

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Question 276533: solve for x.
3%2810%5E2%5Ex%2B1%29=5%2810%5E2%5Ex-1%29
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3(10^2^x+1)=5(10^2^x-1)
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3(100^x+1) = 5(100^x-1)
3*100^x + 3 = 5*100^x - 5
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2*100^x = 8
100^x = 4
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Take the log to get:
x log(100) = log(4)
2x = log(4
x = [log(4)]/2
x = 0.3010..
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cheers,
Stan H.