SOLUTION: Soybean meal is 18% protein, cornmeal is 9% protein.How many pounds of each should be mixed in order to get 360lb of mixture that is 10% protein? a. how many pounds of cornmea

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Question 274517: Soybean meal is 18% protein, cornmeal is 9% protein.How many pounds of each should be mixed in order to get 360lb of mixture that is 10% protein?

a. how many pounds of cornmeal should be in the mixture?

b. how many pounds of soybean meal should be in the mixture?
Answer by anantha(86) (Show Source):
You can put this solution on YOUR website!
let no of pounds of soybean meal be x pounds
and no of pounds of cornmeal be y pounds
x pounds of 18% protein and y pounds of 9% protein should be mixed we get 360lb of 10% protein
x+y=360lb -------(1)equation
y=360-x(i.e; for isolating y subtract x from both sides)
x * (18%)+ y*(9%) =360*(10%)
x*(18/100)+y*(9/100)=360*(10/100)
18x/100+9y/100=3600/100
multiplying every term by 100
(18x/100)*100+(9y/100)*100=(3600/100)*100
after removing 100 on both sides we have
18x+9y=3600------------(2) equation
substitute y value in 2 equation
18x+9(360-x)=3600
18x+9*360-9*x=3600
18x+3240-9x=3600
9x+3240=3600(subtracting 9x from 18x we get 9x)
isolate x on one side subtract 3240 on both sides
9x+3240-3240=3600-3240
9x=360
dividing both sides by 9 we get
9x/9 =360/9
x=40
substitute x value in y=360-x
y=360-x
y=360-40=320
no of pounds of soybean meal=40 pounds
no of pounds of cornmeal=320 pounds