SOLUTION: 1) The average of four numbers is 25. Three of the numbers are 10,55,and 15. a) write an equation representing this situation. b) Solve the four number. Problem #2 A. The l

Algebra ->  Equations -> SOLUTION: 1) The average of four numbers is 25. Three of the numbers are 10,55,and 15. a) write an equation representing this situation. b) Solve the four number. Problem #2 A. The l      Log On


   



Question 272266: 1) The average of four numbers is 25. Three of the numbers are 10,55,and 15. a) write an equation representing this situation. b) Solve the four number.

Problem #2
A. The length of the retangular garden is 5 yards more than its width. If the area of the garden is 36 square yards, write the polynomial in a standard form that could be used to find the dimensions of the garden.
B. Determine the dimensions of the garden using this polynomial.

Thanks for your help!
Nathan Diaz
ltd7@msn.com

Found 2 solutions by Alan3354, Earlsdon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1) The average of four numbers is 25. Three of the numbers are 10,55,and 15. a) write an equation representing this situation. b) Solve the four number.
The sum is 4 times the average = 100
The 4th number is 100 - (10+55+15)
= 100 - 80
= 20
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Problem #2
A. The length of the retangular garden is 5 yards more than its width. If the area of the garden is 36 square yards, write the polynomial in a standard form that could be used to find the dimensions of the garden.
Area = L*W
L = W+5
Area = W*(W+5) = W^2 + 5W = 36
W^2 + 5W - 36 = 0
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B. Determine the dimensions of the garden using this polynomial.
W^2 + 5W - 36 = 0
(W - 4)*(W + 9) = 0
W = 4
L = 9
(Ignore the -9 solution)
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Thanks for your help!
Nathan Diaz
ltd7@msn.com
----------------
PS It's not a good idea to show your last name with your email address.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
1)
a) The average of a set of numbers is found by dividing the sum of the numbers by the count of the numbers added, so, let x be the missing number, then...
highlight%28%2810%2B55%2B15%2Bx%29%2F4+=+25%29
b) %2880%2Bx%29%2F4+=+25 Multiply both sides by 4.
80%2Bx+=+100 Subtract 80 from both sides.
highlight%28x+=+20%29 This is the fourth number.
2)The area of a rectangle is given by:
A+=+L%2AW where: L = length and W = width. Substutiute A = 36 and L = W+5
36+=+%28W%2B5%29%2AW Convert to the standard form for a quadratic equation.
W%5E2%2B5W-36+=+0 Factor.
%28W%2B9%29%28W-4%29+=+0 Apply the zero product rule.
W%2B9+=+0or W-4+=+0 so...
highlight%28W+=+4%29yards, and...
L+=+W%2B5
highlight%28L+=+9%29yards.