SOLUTION: 4y^2+9=0
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Question 265125
:
4y^2+9=0
Answer by
checkley77(12844)
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4y^2+9=0
y=(0+-sqrt[0^2-4*4*9])/2*4
y=(+-sqrt[-144])/8
y=(+-12i)/8
y=+-12i/8
y=+-1.5i ans.