SOLUTION: A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t2 + 512t + 64. Find the height of the shell 24 seconds after it is fired. (Simplify the answer as mu

Algebra ->  Equations -> SOLUTION: A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t2 + 512t + 64. Find the height of the shell 24 seconds after it is fired. (Simplify the answer as mu      Log On


   



Question 264528: A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t2 + 512t + 64. Find the height of the shell 24 seconds after it is fired. (Simplify the answer as much as possible.)
s= ? ft.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
s = f(t) = -16t2 + 512t + 64
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Sub 24 for t
s = -16*24^2 + 512*24 + 64
Add those up.