You can put this solution on YOUR website! (x+1)/(x+1) + (5)/(x+2) = (3)/(x+1) times every thing by ((x+1)(X+2))
((x+1)(x+2))+((5(x+1))= ((3(X+2)) multiply together
(x^2+3x+2)+(5x+5)=(3x+6) add like terms
x^2 + 8x + 7= 3x + 6 Subtract 3x and 6 from both sides
. -3x - 6 -3x - 6
x^2 +5x+1=0 now u have a quadratic equation
You can put this solution on YOUR website! Hello,
First off let's get rid of the fractions by multiplying each (x+1)(x+2) to get:
(x+1)(x+2) + (5)(x+1) = (3)(x+2) This can be expanded out tobe:
x^2+3x+2+5x+5=3x+6 Now combine terms and subtract 3x and 6 from both sides to get 5:
x^2+5x+1=0
Now apply the quadratic equation: {{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }
x = (-5 +- sqrt(21))/2
There we go!
RJ
www.math-unlock.com