SOLUTION: I am a parent that didn't get to finish in high school and my son has this problem and i don't know to write the equation out. thank you for your time. Here is the problem. Air

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Question 259889: I am a parent that didn't get to finish in high school and my son has this problem and i don't know to write the equation out. thank you for your time. Here is the problem.
Air Travel: A jet leaves the Chalotte, Noth Carolina, airport traveling at an aveage rate of 564 km/h. Another plane leaves the airport one half hour later traveling at 744 km/h in the same direction. Use an equation to find how long the second jet will take to overtake the first.
Found 3 solutions by rfer, richwmiller, ankor@dixie-net.com:
Answer by rfer(16322)   (Show Source):
You can put this solution on YOUR website!
overtake speed is 744-564=180 km/h
A is 564/2=282km ahead
282/180=1.57 hrs or 1hr 34 min for B to overtake A

Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website!
The planes will be going the same distance but not a tthe ssame time
rt=d
rate*time=distance
eg 60 mph*2 hours =120 miles
rt=rt
we know the rates ( speeds)
564*t=744*(t-1/2)
564t=744t-744*1/2
Your son should be able to finish this.
Usually the hard part is setting up the equations.
t=31/15
2 hours 1/15 hour
1/15 of an hour is 4 minutes
2hr 4 minutes
that needs to be convert to hours.
t is the amount of time for the plane at 564 mph
t-1/2 is the other plane

Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
A jet leaves the Charlotte, North Carolina, airport traveling at an average rate of 564 km/h.
Another plane leaves the airport one half hour later traveling at 744 km/h in the same direction.
Use an equation to find how long the second jet will take to overtake the first.
:
:
Change 30 min to .5 hrs
:
Let t = time required for the faster jet catch up with the 1st jet
then
(t+.5) = travel time of the slower plane
:
When this happens, the two planes will have traveled the same distance.
:
Write a dist equation: dist = speed * time
Fast jet dist = slow jet dist
744t = 564(t+.5)
744t = 564t + 282
744t - 564t = 282
180t = 282
t =
t = 1.567 hrs or 1 + .567(60) = 1 hr 34 min