i dont know how to make the following into an equation.
the perimeter of a rectangle is 40 ft. the width is 2ft more then half the length. find the length and width
the formula for perimeter is:
P = 2L + 2W
the width, W, is 2ft more then half the length, L.
So W equals 2 more than
times L.
So W = 2 more than
L
To make something 2 more than it is, you add 2 to it.
So W =
L + 2
Now go back to the formula
P = 2L + 2W.
Since "the perimeter of a rectangle is 40 ft", put 40 where the P is
and (
L + 2) where the W is
40 = 2L + 2(
L + 2)
Can you solve that for L? If not post again asking how.
Answer: L = 12
Then you go back to the equation:
W =
L + 2
and substitute 12 for L
and you get 8
So the length is 12 feet and the width is 8 feet.
Edwin