SOLUTION: Please factor is possible; otherwise, write "not factorable". 9X squared plus 6X plus 1. Sorry I did not know how to insert the squared sign.

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Question 255113: Please factor is possible; otherwise, write "not factorable".
9X squared plus 6X plus 1.
Sorry I did not know how to insert the squared sign.

Found 2 solutions by stanbon, richwmiller:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
9X squared plus 6X plus 1.
----
9x^2 + 6x + 1
9x^2 + 3x + 3x + 1
3x(3x+1) + (3x+1)
(3x+1)(3x+1)
================
Cheers,
Stan H.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
9x^2+6x+1
(3x+1)^2
square sign is ^2 using ^ above the 6
Do you also not know the plus sign since you wrote out plus?
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 9x%5E2%2B6x%2B1, we can see that the first coefficient is 9, the second coefficient is 6, and the last term is 1.



Now multiply the first coefficient 9 by the last term 1 to get %289%29%281%29=9.



Now the question is: what two whole numbers multiply to 9 (the previous product) and add to the second coefficient 6?



To find these two numbers, we need to list all of the factors of 9 (the previous product).



Factors of 9:

1,3,9

-1,-3,-9



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 9.

1*9 = 9
3*3 = 9
(-1)*(-9) = 9
(-3)*(-3) = 9


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 6:



First NumberSecond NumberSum
191+9=10
333+3=6
-1-9-1+(-9)=-10
-3-3-3+(-3)=-6




From the table, we can see that the two numbers 3 and 3 add to 6 (the middle coefficient).



So the two numbers 3 and 3 both multiply to 9 and add to 6



Now replace the middle term 6x with 3x%2B3x. Remember, 3 and 3 add to 6. So this shows us that 3x%2B3x=6x.



9x%5E2%2Bhighlight%283x%2B3x%29%2B1 Replace the second term 6x with 3x%2B3x.



%289x%5E2%2B3x%29%2B%283x%2B1%29 Group the terms into two pairs.



3x%283x%2B1%29%2B%283x%2B1%29 Factor out the GCF 3x from the first group.



3x%283x%2B1%29%2B1%283x%2B1%29 Factor out 1 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%283x%2B1%29%283x%2B1%29 Combine like terms. Or factor out the common term 3x%2B1



%283x%2B1%29%5E2 Condense the terms.



===============================================================



Answer:



So 9%2Ax%5E2%2B6%2Ax%2B1 factors to %283x%2B1%29%5E2.



In other words, 9%2Ax%5E2%2B6%2Ax%2B1=%283x%2B1%29%5E2.



Note: you can check the answer by expanding %283x%2B1%29%5E2 to get 9%2Ax%5E2%2B6%2Ax%2B1 or by graphing the original expression and the answer (the two graphs should be identical).