SOLUTION: x ♣ y = x^2 + y^2 (x ♣ y) + 13 = x ♣ z x = 3 y and z are positive integers What is z ?

Algebra ->  Equations -> SOLUTION: x ♣ y = x^2 + y^2 (x ♣ y) + 13 = x ♣ z x = 3 y and z are positive integers What is z ?      Log On


   

Question 252798: x ♣ y = x^2 + y^2 (x ♣ y) + 13 = x ♣ z
x = 3 y and z are positive integers What is z ?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Although I do play poker, the last I knew ♣ was not a mathematical operation.