SOLUTION: The sum of the measures of any triangle is 180 degrees. Find the angle measures of a triangl if the second angle measures 10 degerees less than twice the first, and the third angle

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Question 248482: The sum of the measures of any triangle is 180 degrees. Find the angle measures of a triangl if the second angle measures 10 degerees less than twice the first, and the third angle measures 25 degrees more than the second.
Found 2 solutions by richwmiller, College Student:
Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website!
Let a,b and c be the angles of the triangle.
a+b+c=180
b=2a-10
solve for a
b+10=2a
(b+10)/2=a
c=b+25
We now have three equations with three variables.
a=35
b=60
c=85
but how did we get that.
first substitute b+25 for c
(b+10)/2+b+b+25=180
consolidate
(b+10)/2+2b+25=180
subtract 25 from both sides
(b+10)/2+2b=155
multiply by 2 (both sides)
b+10+4b=310
subtract 10 (both sides)
b+4b=300
combine
5b=300
divide by 5(both sides)
b=60
c=b+25=25+60=85
a=(b+10)/2=(60+10)/2=70/2=35

Answer by College Student(505) (Show Source):
You can put this solution on YOUR website!
The sum of the measures of any triangle is 180 degrees. Find the angle measures of a triangle if:

1. the second angle measures 10 degrees less than twice the first and
2. the third angle measures 25 degrees more than the second

Let x = one angle
Let 2x-10 = second angle
Let (2x-10)+25 = third angle ...same as... 2x+15
Their sum equals 180 degrees

Therefore, the equation becomes:

Now add like terms and solve for x to determine the first angle.
Plug this value in 2x-10 to determine the second value.
Plug the x value in 2x+15 to determine the third angle.

They must all add up to 180. I'll let you take it from here!