SOLUTION: Translate the problem situation to a system of equations. Do not attempt to solve. The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the len

Algebra ->  Equations -> SOLUTION: Translate the problem situation to a system of equations. Do not attempt to solve. The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the len      Log On


   

Question 245860: Translate the problem situation to a system of equations. Do not attempt to solve.
The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the length. What are the dimensions? (Let W represent the width and L represent the length.)
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Here we are just asked to set up the equations and not solve them.
The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the length. What are the dimensions? (Let W represent the width and L represent the length.)
the formula for the perimeter of a rectangle is 2L+2W=Perimeter
we know that W=L-25
the perimeter =234
and that 2L+2W=234
So now we have two equations with two variables.
There is enough information to solve them.
We can substitute L-25 in the last equation for every W