-50t + 10 = 35
There are two terms on the left and one term on the right.
Use addition or subtraction of the same quantity on both sides to:
1. Get rid of all terms on the left that DO NOT contain the variable
2. Get rid of all terms on the right that DO contain the variable
-50t + 10 = 35
The first term -50x contains the variable and is on the left, so we do
not want to get rid of it. The next term on the left is +10. It is on
the left side and DOES NOT contain the variable, so we need to get rid of
the +10 on the left, by adding it's opposite -10 to both sides.
-50t + 10 = 35
-10 -10
————————————————————
-50t = 25
3. When there is only one term with a avariable on the left, and only
one term on the right without a variable, then divide both sides by the
coefficient ot the variable.
So we divide both sides by -50
-50t 25
——————— = —————
-50 -50
The left sides reduces to just t, and the right side reduces to -1/2
t = -1/2
Edwin
AnlytcPhil@aol.com