SOLUTION: factor 9x^2+3x-2

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Question 23858: factor
9x^2+3x-2

Answer by PeterC(8) About Me  (Show Source):
You can put this solution on YOUR website!
A quadratic funtion ax%5E2%2Bbx%2Bc can be factored as %28a%29%28x-r1%29%28x-r2%29,
where r1 and r2 are the roots (solutions) to the equation ax%5E2+%2B+bx+%2B+c+=+0.
We can find r1 and r2, using the quadratic formula
%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29.
Here,
and

Therefore, our factors are: %289%29+%2A+%28x+-+1%2F3%29+%2A+%28x+%2B+2%2F3%29
What I have shown (creating a factored expression by finding the roots of a polynomial equation) is a brute-force method that will always work. However, you can often solve the problem by examination, by posing the question, "What are two numbers whose sum is b/a and product is c/a?" (It is a bit easier to do this if a = 1.) In fact, the usual reason for factoring a quadratic expression is that it gives us a shortcut to finding its roots (which are the negatives of those two numbers). If we can recognize the numbers that create our desired sum and product, we can avoid a somewhat laborious computation with the quadratic formula.
In this problem,
9x%5E2+%2B+3x+-+2+=+%283x-1%29%283x%2B2%29+=+9%28x-1%2F3%29%28x%2B2%2F3%29