SOLUTION: Thank you in advance for your help I am asked to solve the equation {{{2/(x-3) - 4/(x+3) = 8/(x^2-9)}}}

Algebra ->  Equations -> SOLUTION: Thank you in advance for your help I am asked to solve the equation {{{2/(x-3) - 4/(x+3) = 8/(x^2-9)}}}      Log On


   

Question 236420: Thank you in advance for your help
I am asked to solve the equation
2%2F%28x-3%29+-+4%2F%28x%2B3%29+=+8%2F%28x%5E2-9%29
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2%2F%28x-3%29+-+4%2F%28x%2B3%29+=+8%2F%28x%5E2-9%29 Start with the given equation.


2%2F%28x-3%29+-+4%2F%28x%2B3%29+=+8%2F%28%28x-3%29%28x%2B3%29%29 Factor the last denominator.


Multiply EVERY term by the LCD %28x-3%29%28x%2B3%29 to clear out the fractions.


%28x%2B3%292-%28x-3%294=8 Simplify


2%28x%2B3%29-4%28x-3%29=8 Rearrange the terms.


2x%2B6-4x%2B12=8 Distribute.


-2x%2B18=8 Combine like terms on the left side.


-2x=8-18 Subtract 18 from both sides.


-2x=-10 Combine like terms on the right side.


x=%28-10%29%2F%28-2%29 Divide both sides by -2 to isolate x.


x=5 Reduce.


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Answer:

So the solution is x=5