SOLUTION: How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution? (Remember that pure antifreeze is 100% = 1.)

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Question 235012: How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution? (Remember that pure antifreeze is 100% = 1.)

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(total liters of pure)/(total liters) = 60%
Let x = liters of pure (100%) antifreeze to be added
%28x+%2B+.4%2A12%29%2F%28x+%2B+12%29+=+.6
x+%2B+4.8+=+.6%2A%28x+%2B+12%29
x+%2B+4.8+=+.6x+%2B+7.2
.4x+=+2.4
x+=+6
6 liters of pure antifreeze must be added