SOLUTION: a bus traveling at the rate of 30 miles per hour left the city at 11:45 a.m. A car following the bus at 45 miles per hour left the city at noon.At what time will the driver catch

Algebra ->  Equations -> SOLUTION: a bus traveling at the rate of 30 miles per hour left the city at 11:45 a.m. A car following the bus at 45 miles per hour left the city at noon.At what time will the driver catch       Log On


   

Question 225782: a bus traveling at the rate of 30 miles per hour left the city at 11:45 a.m. A car following the bus at 45 miles per hour left the city at noon.At what time will the driver catch up with the bus?
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
bus has 7.5 mi lead
car overtaking at 15 mph
7.5/15=.5 hrs
meeting time 11:45 am +30 min=12:15 pm