SOLUTION: Write an equation for the line described as slope=-3/5 and passes through (7,6). Write in slope intercept form.

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Question 217758: Write an equation for the line described as slope=-3/5 and passes through (7,6). Write in slope intercept form.
Found 2 solutions by stanbon, drj:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation for the line described as slope=-3/5 and passes through (7,6). Write in slope intercept form.
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Form: y = mx + b
You know m,x, and y ; so solve for "b"
6 = (-3/5)(7) + b
6 = -21/5 + b
30/5 + 21/5 = b
b = 51/5
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Equation:
y = (-3/5)x + (51/5)
====================
Cheers,
Stan H.

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation for the line described as slope=-3/5 and passes through (7,6). Write in slope intercept form.

Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept b at x=0 or point (0,b). Here, the slope m=-3/5.

Step 2. The slope m is given as

m=%28y2-y1%29%2F%28x2-x1%29

Step 3. Let (x1,y1)=(6,7) or x1=7 and y1=6. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.

Step 4. Now we're given m=-3%2F5. Substituting above values and variables in the slope equation m yields the following steps:

m=%28y2-y1%29%2F%28x2-x1%29

-3%2F5=%28y-6%29%2F%28x-7%29

Step 5. Multiply (x-7) to both sides to get rid of denominators on both sides of equation.

%28x-7%29%2A%28-3%2F5%29=%28x-7%29%28y-6%29%2F%28x-7%29

-3x%2F5%2B21%2F5=y-6

Step 6. Now add +6 to both sides of equation to solve for y.

-3x%2F5%2B21%2F5%2B6=y-6%2B6

-3x%2F5%2B51%2F5=y


Step 7. ANSWER: The equation is -3x%2F5%2B51%2F5=y

Here's a graph below and note the slope and y-intercept at x=0 or point (0, 51/5) and the x-intercept at y=0 or at point (17, 0)and note it is consistent with the equation when substituting these

graph%28500%2C500%2C+-10%2C20%2C-5%2C15%2C+-3x%2F5%2B51%2F5%29

Note: the above equation can be rewritten in standard form as

3x%2B5y=51

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J