SOLUTION: Can you please show the progression to get to a solution of "1/8" for the problem below? (1/5 – x) ÷ 27/50 = x ÷ 9/10 x = 1/8 Thank you!

Algebra ->  Equations -> SOLUTION: Can you please show the progression to get to a solution of "1/8" for the problem below? (1/5 – x) ÷ 27/50 = x ÷ 9/10 x = 1/8 Thank you!      Log On


   

Question 214934: Can you please show the progression to get to a solution of "1/8" for the problem below?
(1/5 – x) ÷ 27/50 = x ÷ 9/10
x = 1/8
Thank you!
Found 2 solutions by Theo, vleith:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
((1/5) - x) / (27/50) = x / (9/10)
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This equation is the same as:
x%2F%289%2F10%29+=+%28%281%2F5%29-x%29%2F%2827%2F50%29
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x+%2F+%289%2F10%29 is the same as x+%2A+%2810%2F9%29 = %2810%2Ax%29%2F9
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%28%281%2F5%29+-+x%29+%2F+%2827%2F50%29 is the same as %28%281%2F5%29-x%29+%2A+%2850%2F27%29 = %28%28%281%2F5%29-x%29+%2A+50%29%2F27
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Your equation becomes:
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%28%28%281%2F5%29-x%29+%2A+50%29%2F27 = %2810%2Ax%29%2F9
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Multiply both sides of this equation by 27 to get:
%28%28%281%2F5%29-x%29+%2A+50%29 = %2827%2A10%2Ax%29%2F9 which becomes:
%28%28%281%2F5%29-x%29%2A50%29 = %2830%2Ax%29
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%28%28%281%2F5%29-x%29%2A50%29 becomes %2810-50%2Ax%29 so your equation becomes:
10-50%2Ax+=+30%2Ax
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add 50%2Ax to both sides of this equation to get:
10+=+30%2Ax+%2B+50%2Ax which becomes:
10+=+80%2Ax
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divide both sides of this equation by 80 to get:
x+=+1%2F8
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Answer by vleith(2983) About Me  (Show Source):