SOLUTION: kirra is two years older then reggie. reggie is six times as old as delia. the average of their ages is nine years and four months. how old is each of them?
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Question 213985This question is from textbook
: kirra is two years older then reggie. reggie is six times as old as delia. the average of their ages is nine years and four months. how old is each of them? This question is from textbook
You can put this solution on YOUR website! Let K = Kirra's age, R = Reggie's age, and D = Delia's age.
K = R+2 "Kirra is two years older than Reggie." Rewrite as K = R-2
R = 6D "Reggie is six times as old as Delia."
K+R+D can be expressed as: Simplify. Multiply both sides by 3. Subtract 2 from both sides. Divide by 13.
Kirra is 14 years old, Reggie is 12 years old and Delia is 2 years old.
You can put this solution on YOUR website! Kirra is two years older then Reggie. Reggie is six times as old as Delia. the average of their ages is nine years and four months. how old is each of them?
Step 1. Let x be the age of Delia. Let 6x be the age of Reggie. Let 6x+2 be the age of Kirra
Step 2. Let Average ages be A= years where 4/12=1/3 (4 months = 1/3 year)
Step 3. or
Delia's age. Then
Reggie's age
Kirra's age
Step 4. ANSWER: Delia is 2 years old, Reggie is 12 years old and Kirra is 14 years old.
As a check the average is
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
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