Question 213777: 1. x^3+216=0
2. 5x^3+30x^2+45x=0
3. 1/x^2+8/x+15=0
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! 1. x^3+216=0
Subtracting 216 from both sides of equation
Answer
2. 5x^3+30x^2+45x=0
where we have x=0, 5x+15=0 and x+3=0. Solving yields
x=0, x=-3 and x=-3, or solve quadratic equation using following steps,
Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored: 
Again, the answer is: -3, -3.
Here's your graph:
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3. 1/x^2+8/x+15=0 Multiply by x^2 to get rid of denominator
where we have 5x+1=0 and 3x+1=0. Solving yields
So x=(-1/5) and x=(-1/3)
We can also use the quadratic formula as follows:
Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=4 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: -0.2, -0.333333333333333.
Here's your graph:
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I hope the above steps were helpful.
And good luck in your studies!
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
Respectfully,
Dr J
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