SOLUTION: Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle.
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Question 213480: Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle. Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle.
Step 1. Let l = 2w-9 be the length of rectangle and let w be the width
Step 2. Let P = 42 meters be the perimeter. Perimeter means adding the 4 sides of a rectangle. So,
Step 3. Add 18 to both sides of equation to get 4w by itself
Step 4. Divide 6 to both sides of equation
Step 5. w = 10 meters is the width of the rectangle and length is 11 m since
l=2w-9=11
Check P=2w+2l=2(10)+2(11)=20+22=42 So w = 10 meters and l = 11 meters is the solution.
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