SOLUTION: Ethan goes on a charity journey. He walks one-tenth of the way at 6km/h, runs one-sixth at 12 km/h, cycles one-fifth at 24km/h, completes the remaining 32km by car at 48km/h. How m
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-> SOLUTION: Ethan goes on a charity journey. He walks one-tenth of the way at 6km/h, runs one-sixth at 12 km/h, cycles one-fifth at 24km/h, completes the remaining 32km by car at 48km/h. How m
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Question 205480This question is from textbook Longman Mathematics for IGCSE Book 1
: Ethan goes on a charity journey. He walks one-tenth of the way at 6km/h, runs one-sixth at 12 km/h, cycles one-fifth at 24km/h, completes the remaining 32km by car at 48km/h. How many kilometres does he travel and how long does it take? This question is from textbook Longman Mathematics for IGCSE Book 1
You can put this solution on YOUR website! Ethan goes on a charity journey. He walks one-tenth of the way at 6km/h, runs one-sixth at 12 km/h, cycles one-fifth at 24km/h, completes thje remaining 32km by car at 48km/h. How many kilometers does he travel and how long it take?
Let the total distance = D km.
Distance walking =
Distance running =
Distance cycling =
Distance by car =
Total distance =
The LCD is 30. So we multiply every term by 30:
Subtract 960 from both sides:
Subtract 30D from both sides:
Divide both sides by -16
So his total distance is 60 km.
Distance walking =
Distance running =
Distance cycling =
Distance by car =
Now we use
Time walking =
Time running =
Time cycling =
Time by car =
Total time =
Total time =
Edwin
He has travelled D/10 + D/6 + D/5 (=7D/15) of the way so has 8D/15 left which is 32 km. Therefore D = 60 km.
t1 = 60/60 = 1 hour
t2 = 60/72 = 50 minutes
t3 = 60/120 = 30 minutes
t4 = 32/48 = 40 minutes
Total time T = t1 + t2 + t3 + t4 = 3 hours.
Checking:
6 km at 6 km/h is an hour (6 km is 1/10)
10 km at 12 km/h is 50 minutes (10 km is 1/6)
12 km at 24 km/h is 30 minutes (12 km is 1/5)
32 km at 48 km/h is 40 minutes (32 km is 8/15)
Total distance is 60 km and total time is 3 hours.
