SOLUTION: please help me solve this equation, I've tried and cannot get the correct answer thanks for your help in advance.
2t-1/3t+1+3t-1/6t+6=t/t+1
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-> SOLUTION: please help me solve this equation, I've tried and cannot get the correct answer thanks for your help in advance.
2t-1/3t+1+3t-1/6t+6=t/t+1
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Question 205053This question is from textbook
: please help me solve this equation, I've tried and cannot get the correct answer thanks for your help in advance.
2t-1/3t+1+3t-1/6t+6=t/t+1 This question is from textbook
You can put this solution on YOUR website! 2t-1/3t+1+3t-1/6t+6=t/t+1
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Factor where you can to get:
(2t-1)/(3t+1)+(3t-1)/(6(t+1)) = t/(t+1)
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Multiply thru by 6(3t+1)(t+1) to get:
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(2t-1)(6(t+1)) + (3t-1)(t+1) = t(6(3t+1)
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Simplify:
6(2t^2+t-1) + 3t^2+2t-1 = 18t^2+6t
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12t^2 + 6t - 6 + 3t^2+2t-1 = 18t^2+6t
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15t^2 + 8t + 7 = 18t^2 + 6t
3t^2 - 2t - 7 = 0
Solve using the quadratic formula.
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Cheers,
Stan H.
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