SOLUTION: Could you please help me factor this completely? 3c^3+6c^2-27c-54) Thanks for any help!!!!

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Question 204105: Could you please help me factor this completely?
3c^3+6c^2-27c-54)
Thanks for any help!!!!

Found 2 solutions by RAY100, scott8148:
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
3c^3 +6c^2 -27c -54
.
Grouping first
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3c^2 (c+2) - 27 ( c+2),,,,,ab -cb= (a-c)(b)
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(3c^2 -27)(c+2)
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3(c^2 -9) (c+2)
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3(c+3)(c-3)(c+2)
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check, let c=1,,,both original and answer = -72,,,,ok

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
3(c^3 + 2c^2 - 9c - 18)

3[c^2(c+2) - 9(c+2)]

3(c+2)(c^2 - 9)

3(c+2)(c+3)(c-3)