SOLUTION: coul you help me about this equation? {{{log(8,(x-1))+1/3=log(8,(x+7))}}}

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Question 202790: coul you help me about this equation?
log%288%2C%28x-1%29%29%2B1%2F3=log%288%2C%28x%2B7%29%29
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Applying "log rules":
log%288%2C%28x-1%29%29%2B1%2F3=log%288%2C%28x%2B7%29%29
log%288%2C%28x-1%29%29+-+log%288%2C%28x%2B7%29%29+=+-1%2F3
log%288%2C%28x-1%29%2F%28x%2B7%29%29+=+-1%2F3
%28x-1%29%2F%28x%2B7%29+=+8%5E%28-1%2F3%29
%28x-1%29%2F%28x%2B7%29+=+1%2F8%5E%281%2F3%29
%28x-1%29%2F%28x%2B7%29+=+1%2F2
2%28x-1%29+=+%28x%2B7%29
2x-2+=+x%2B7
x-2+=+7
x+=+9