SOLUTION: Solve the inequality 4k^3-6k^3(< or =)4k possible answers: (-infinite,-1/2] or (0,2) (-infinite,-1/2) or (0,2) (-infinite,-1/2] or [0,2] (-infinite,-1/2) or [0,2]

Algebra ->  Equations -> SOLUTION: Solve the inequality 4k^3-6k^3(< or =)4k possible answers: (-infinite,-1/2] or (0,2) (-infinite,-1/2) or (0,2) (-infinite,-1/2] or [0,2] (-infinite,-1/2) or [0,2]      Log On


   



Question 201392: Solve the inequality
4k^3-6k^3(< or =)4k
possible answers:
(-infinite,-1/2] or (0,2)
(-infinite,-1/2) or (0,2)
(-infinite,-1/2] or [0,2]
(-infinite,-1/2) or [0,2]

Found 3 solutions by Theo, ikleyn, greenestamps:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
simplify the left side of the equation to get
-2k^3 <= 4k
divide both sides by k to get
-2k^2 <= 4
divide both sides of the equation by -2 to get
k^2 >= -2
take the square root of both sides of the equation to get
k >= square root of (-2)
to prove your answer is correct you need to.
1. let k = square root (-2) and solve. the equation should hold true.
2. let k be > than square root (-2) and solve. the equation should hold true.
3. let k be < than square root (-2) and solve. the equation should be false.



Answer by ikleyn(53304) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the inequality
4k^3-6k^3 <= 4k
possible answers:
(-infinite,-1/2] or (0,2)
(-infinite,-1/2) or (0,2)
(-infinite,-1/2] or [0,2]
(-infinite,-1/2) or [0,2]
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


To this problem, I'd like to make two comments.


First comment is that the input is given incorrectly: the given inequality is INCONSISTENT with the answers list.


Second comment is that the solution by tutor @Theo is incorrect.
It contains so dangerous errors that are a mortal threat to an inexperienced and gullible reader.

For example, @Theo considers inequality

    -2k^3 <= 4k     (*)


and instructs a reader to divide it by  'k'  to get

    -2k^2 <= 4.     (**)


But inequalities  (*)  and  (**)  are not equivalent,  because if 'k' is negative,
then the inequality sign in  (**)  must be reversed.


Actually,  I do understand perfectly,  how the problem should be modified to make it consistent,
but I will not do it.

Why ? -  Because   (1)   I do not understand why I should worry about it more than the visitor,
              whose direct duty and direct responsibility is to provide a proper input,
and   (2)   because it would be too much to make corrections and then to solve the problem.

It would be a bad method to teach - the result will be a person,  who is not familiar with the notion of responsibility.



Answer by greenestamps(13241) About Me  (Show Source):
You can put this solution on YOUR website!


4k%5E3-6k%5E3%3C=4k

-2k%5E3%3C=4k

Never divide both sides of an equation -- or especially an inequality -- by an expression containing the variable. Doing so will probably, at best, lose some solutions, or it might result in totally incorrect solutions.

Collect all terms on one side of the inequality on the left with "0" on the right and find the solution set by factoring.

2k%5E3%2B4k%3E=0

2k%28k%5E2%2B2%29%3E=0

Since k%5E2%2B2 is always greater than 0,...

2k%3E=0
k%3E=0

ANSWER: [0,infinity)

None of the given answer choices is correct.

Note that the given inequality is curious, since the expression on the left contains two like terms. Since none of the given answer choices is correct for the given inequality, it is highly likely that the given inequality is not correct.