SOLUTION: Would you please show me what steps I am either leaving out or doing wrong in the following equation: {{{(5x+1)/7 - (2x-6)/4 >-4}}}. My answer does not match the one in the book.

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Question 199942This question is from textbook Intermediate Algebra
: Would you please show me what steps I am either leaving out or doing wrong in the following equation: . My answer does not match the one in the book. Thank you. This question is from textbook Intermediate Algebra

Found 2 solutions by RAY100, Edwin McCravy:
Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website!
Revised due to problem statement revision
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(5x+1) / 7 - (2x-6) / 4 > -4
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4(5x+1) /28 - 7(2x-6)/28 > -4
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( 20x +4 -14x +42) / 28 > -4
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( 6x +46) / 28 > -4
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6x + 46 > -4 * 28
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6x +46 > -112
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6x > -158
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x> -26 1/3
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Answer by Edwin McCravy(20055) (Show Source):
You can put this solution on YOUR website!
Ray's solution is incorrect.
Here is the correct solution by Edwin:

We will clear of fractions. Put parentheses around each term and write the on the right as so that every term will be a fraction: The LCD of all the denominators is Multiply every term through by Cancel the 7 into the 28, getting 4 Cancel the 4 into the 28 in the second term, getting 7 Multiply the by the on the right getting What's left is The we remove the parentheses by distributing: The solution set in interval notation is (,) Edwin