SOLUTION: what is c in 32+4(c-1)=-(4c+5)?

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Question 199912: what is c in 32+4(c-1)=-(4c+5)?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
32%2B4%28c-1%29=-%284c%2B5%29 Start with the given equation.


32%2B4c-4=-4c-5 Distribute.


4c%2B28=-4c-5 Combine like terms on the left side.


4c=-4c-5-28 Subtract 28 from both sides.


4c%2B4c=-5-28 Add 4c to both sides.


8c=-5-28 Combine like terms on the left side.


8c=-33 Combine like terms on the right side.


c=%28-33%29%2F%288%29 Divide both sides by 8 to isolate c.


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Answer:

So the solution is c=-33%2F8 which in decimal form is c=-4.125.