SOLUTION: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped. Find h(1). How
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-> SOLUTION: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped. Find h(1). How
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Question 199107: A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped. Find h(1). How long does it take for the ball to fall to the earth? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A ball is dropped from a height of 64 feet. Its height above the earth in feet is given by h(t ) = -16t2 + 64, where t is the number of seconds after it is dropped. Find h(1). How long does it take for the ball to fall to the earth?
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h(1) = -16 + 64 = 48 feet
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Set h = 0 to find when it impacts
0 = -16t^2 + 64
t^2 = 4
t = 2 seconds (ignore the -2)
