SOLUTION: What amount of each mixture, one 95% alcohol the other 15% alcohol must be used to make 10 liters of a mixture which is 45% alcohol?
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Question 198079: What amount of each mixture, one 95% alcohol the other 15% alcohol must be used to make 10 liters of a mixture which is 45% alcohol? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What amount of each mixture, one 95% alcohol the other 15% alcohol must be used to make 10 liters of a mixture which is 45% alcohol?
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Equation:
alcohol + alcohol = alcohol
0.95x + 0.15(10-x) = 0.45*10
Multiply thru by 100 to get:
95x + 150 - 15x = 450
80x = 300
x = 3.75 liters (amt. of 95% solution)
10-x = 6.25 liters (amt. of 15% solution)
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Cheers,
stan H.
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