SOLUTION: I'm not sure what I'm doing wrong in this problem. I got part of the problem but the other half it says it's incorrect can you help me
Find the domain of the function. If the do
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Find the domain of the function. If the do
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Question 197795: I'm not sure what I'm doing wrong in this problem. I got part of the problem but the other half it says it's incorrect can you help me
Find the domain of the function. If the domain can be specified by only one interval, use (NONE, NONE) for the second interval.
g(x) = sqrt(x)/(7 x^2 + 6 x - 1)
thanks! Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! g(x) = sqrt(x)/(7 x^2 + 6 x - 1)
7x^2+6x-1
=(7x^2+7x-x-1)
=7x(x+1)-(x+1)
=(7x-1)(x+1)
.
x cannot be less than zero because then the denominator would not be a real number.
x cannot equal 1/7 because there would be a division by zero error.
.
x[0, 1/7)U(1/7, infinity)
.
Ed
