SOLUTION: Please help me with this problem Solve by using quadric formula x^2+8x=3 We substitute a=1, b=8 and c=3

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Question 196738: Please help me with this problem
Solve by using quadric formula x^2+8x=3 We substitute a=1, b=8 and c=3
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B8x%2B3+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%288%29%5E2-4%2A1%2A3=52.

Discriminant d=52 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-8%2B-sqrt%28+52+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%288%29%2Bsqrt%28+52+%29%29%2F2%5C1+=+-0.394448724536011
x%5B2%5D+=+%28-%288%29-sqrt%28+52+%29%29%2F2%5C1+=+-7.60555127546399

Quadratic expression 1x%5E2%2B8x%2B3 can be factored:
1x%5E2%2B8x%2B3+=+%28x--0.394448724536011%29%2A%28x--7.60555127546399%29
Again, the answer is: -0.394448724536011, -7.60555127546399. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B8%2Ax%2B3+%29