SOLUTION: I need help to find the beginning equation the following word problem-Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount o
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Question 196736: I need help to find the beginning equation the following word problem-Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current?
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Downstream DATA:
distance = 12 miles ; rate = 15+c mph ; time = d/r = 12/(15+c)
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Upstream DATA:
distance = 9 miles ; rate = 15-c ; time = d/r = 9/(15-c)
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Equation:
time up = time down
9/(15-c) = 12/(15+c)
Cross-multiply:
9(15+c) = 12(15-c)
135 + 9c = 180 - 12c
21c = 45
c = 2.5 mph (speed of the current)
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Cheers,
Stan H.
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