SOLUTION: Three consecutive even integers are such that the square of the third is 100 more than the square of the second. Find 3 integers. I am sooo lost.
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Question 191731This question is from textbook
: Three consecutive even integers are such that the square of the third is 100 more than the square of the second. Find 3 integers. I am sooo lost.
Thank You This question is from textbook
You can put this solution on YOUR website! Three consecutive even integers: x, (x+2), (x+4)
:
the square of the third is 100 more than the square of the second.
(x+4)^2 = (x+2)^2 + 100
FOIL
x^2 + 8x + 16 = x^2 + 4x + 4 + 100
:
x^2 + 8x + 16 = x^2 + 4x + 104
:
Arrange the x's on the left, numbers on the right:
x^2 - x^2 + 8x - 4x = 104 - 16
:
4x = 88
x =
x = 22, 24, 26; are the numbers
:
:
Check solution in the statement:
"the square of the third is 100 more than the square of the second."
26^2 = 24^2 + 100
676 = 576 + 100
