SOLUTION: The sum of mulptiplicative inverse of two positive even integers is 5/12.find the integers .

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Question 191317: The sum of mulptiplicative inverse of two positive even integers is 5/12.find the integers .
Answer by MathTherapy(10552) About Me  (Show Source):
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There isn’t enough information to this problem for it to be solved.
However, I assumed that it was supposed to read the following:
“The sum of the multiplicative inverse of two positive CONSECUTIVE even integers is 5/12.find the integers.”
From this assumption, let the first even integer be x
Then the following consecutive even integer will be x + 2
Since the assumption is that the sum of the multiplicative inverse of these 2 numbers is 5/12, then 1%2Fx++%2B+1%2F%28x+%2B+2%29+=+5%2F12
Then, 12x + 24 + 12x = 5x(x + 2)
24x++%2B++24++=++5x%5E2+%2B+10x
5x%5E2+-+14x+-++24++=++0
5x%5E2+-+20x+%2B+6x++-++24++=++0
5x(x – 4) + 6(x – 4) = 0
(5x + 6)(x – 4) = 0

Since 5x + 6 = 0 will produce a decimal, we eliminate this x-value as it was given that the 2 numbers are INTEGERS, or whole numbers. Therefore, the first even integer is 4, which makes the second even integer, 6.