Question 187568: I need to factor this problem completely, not quite sure how to though.
16x^4–40x^2+9
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! I need to factor this problem completely, not quite sure how to though.
16x^4–40x^2+9
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It'll be
(ax^2 + b)*(cx^2 + d) a, b, c & d are integers.
a*c = 16
b*d = 9
ad + bc = -40
a & c will be 1, 2, or 4
b & d will be 1 or 3
Since -40 is not divisible by 3, b & d are 1 and 9.
(4x^2 - 1)*(4x^2 - 9)
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It's just a matter of "doodling" until you find it.
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