SOLUTION: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13.
I tried to solve the above problem and came up with the following answer:
-5y/5=-4x/5
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-> SOLUTION: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13.
I tried to solve the above problem and came up with the following answer:
-5y/5=-4x/5
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Question 187172: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13.
I tried to solve the above problem and came up with the following answer:
-5y/5=-4x/5+13/5.... y=-4/5x+13/5 ...(slope=-4/5. The answer is supposed to be y=-4/5x+17/5. I don't understand where 17 came from.
Thank you for your help with this problem.
Judy Answer by jim_thompson5910(35256) (Show Source):
We can see that the equation has a slope and a y-intercept .
Since parallel lines have equal slopes, this means that we know that the slope of the unknown parallel line is .
Now let's use the point slope formula to find the equation of the parallel line by plugging in the slope and the coordinates of the given point .
Start with the point slope formula
Plug in , , and
Rewrite as
Rewrite as
Distribute
Multiply
Subtract 5 from both sides.
Combine like terms.
So the equation of the line parallel to that goes through the point is .