SOLUTION: passing through (-7,-5) and parallel to the line 3x+3y+6=0 please with full steps, thank you

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Question 186625This question is from textbook mathematical analysis
: passing through (-7,-5) and parallel to the line 3x+3y+6=0
please with full steps, thank you This question is from textbook mathematical analysis

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
First, I'll find the slope of
3x+%2B+3y+%2B+6+=+0
3y+=+-3x+-+6
y+=+-x+-+2
This is in the form y+=+mx+%2B+b
where m= slope, and
m+=+-1
Any line parallel to this one will
also have m+=+-1
The point-slope formula is
%28y+-+y%5B1%5D%29%2F%28x+-+x%5B1%5D%29+=+m
I'm given (-7,-5), so
x%5B1%5D+=+-7
y%5B1%5D+=+-5
m+=+-1
%28y+-+%28-5%29%29%2F%28x+-+%28-7%29%29+=+-1
%28y+%2B+5%29%2F%28x+%2B+7%29+=+-1
Multiply both sides by x+%2B+7
y+%2B+5+=+-x+-+7
Add x+%2B+7 to both sides
x+%2B+y+%2B+12+=+0 answer
check answer
Does it go through (-7,-5)?
-7+-+5+%2B+12+=+0
-12+%2B+12+=+0
OK