SOLUTION: Can you show me step by step how to complete the square? 1.) 3t^2 + 24t-13 2.) 4s^2+s+2

Algebra ->  Equations -> SOLUTION: Can you show me step by step how to complete the square? 1.) 3t^2 + 24t-13 2.) 4s^2+s+2       Log On


   



Question 181102: Can you show me step by step how to complete the square?
1.) 3t^2 + 24t-13
2.) 4s^2+s+2

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
complete the square?
1.) 3t^2 + 24t-13
The coefficient of t^2 has to be 1, divide each term by 3, results:
t^2 + 8t - 13%2F3 = 0
:
t^2 + 8t + ___ = 13%2F3
Find the term that will complete the square; square half of the coefficient of t
.5*8=4; 4^2=16; add to both sides
t^2 + 8t + 16 = 13%2F3 + 16
:
t^2 + 8t + 9 = 13%2F3 + 48%2F3; change 16 to thirds
:
(t + 4)^2 = 61%2F3
Find the square root of both sides:
t + 4 = +/-sqrt%2861%2F3%29
subtract 4 from both sides, we have two solutions
t = -4 +sqrt%2861%2F3%29
and
t = -4 -sqrt%2861%2F3%29
:
:
;
2.) 4s^2+s+2
Divide each term by 4 to make the coefficient of s^2 = 1, results
s^2 + 1%2F4s + 2%2F4 = 0
s^2 + 1%2F4s + ___ = -2%2F4
Complete the square, half of (1/4) = (1/8); (1/8)^2 = (1/64)
s^2 + 1%2F4s + 1%2F64 = -2%2F4 + 1%2F64
s^2 + 1%2F4s + 1%2F64 = -32%2F64 + 1%2F64
s^2 + 1%2F4s + 1%2F64 = -31%2F64
(s + 1%2F8)^2 = -31%2F64
s + 1%2F8 = +/-sqrt%28-31%2F64%29
s = -1%2F8 +/-sqrt%28-31%2F64%29
Extract square root of -1 and square root of (1/64)
s = -1%2F8 +/-1%2F8isqrt%2831%29
Can also be written
s = %28-1+%2B+sqrt%2831%29i%29%2F8
and
s = %28-1+-+sqrt%2831%29i%29%2F8
:
:
Was this sufficient steps?